-32t^2-14t+750=0

Solution for -32t^2-14t+750=0 equation:

-32t^2-14t+750=0

a = -32; b = -14; c = +750;
Δ = b2-4ac
Δ = -142-4·(-32)·750
Δ = 96196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96196}=\sqrt{4*24049}=\sqrt{4}*\sqrt{24049}=2\sqrt{24049}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{24049}}{2*-32}=\frac{14-2\sqrt{24049}}{-64}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{24049}}{2*-32}=\frac{14+2\sqrt{24049}}{-64}
$